\(\def \u#1{\,\mathrm{#1}}\) \(\def \abs#1{\left|#1\right|}\) \(\def \ast{*}\) \(\def \deg{^{\circ}}\) \(\def \ten#1{\times 10^{#1}}\) \(\def \redcancel#1{{\color{red}\cancel{#1}}}\) \(\def \BLUE#1{{\color{blue} #1}}\) \(\def \RED#1{{\color{red} #1}}\) \(\def \PURPLE#1{{\color{purple} #1}}\) \(\def \th#1,#2{#1,\!#2}\) \(\def \lshift#1#2{\underset{\Leftarrow\atop{#2}}#1}}\) \(\def \rshift#1#2{\underset{\Rightarrow\atop{#2}}#1}}\) \(\def \dotspot{{\color{lightgray}{\circ}}}\)
Chapter 3: Linear Motion
6.

Change in Velocity

When I write the Greek letter Δ (delta) in front of a variable, I am talking about the change in that variable, usually between some initial moment and some final moment. For instance, $\Delta\vec v$ is the change in velocity, and $\Delta t$ is the change in time. The change in a variable A is defined as
$$\Delta A=A_f-A_i$$

where $A_i$ is the variable's value at hte initial moment and $A_f$ is its value at the final moment. The change in $A$ is also the value you need to add to the initial value to get the final value:

$$A_f=A_i+\Delta A$$

The change in a vector quantity, like velocity, works exactly the same way: $$\Delta\vec v=\vec v_f-\vec v_i=\vec v_f+(-\vec v_i)$$

Consider this motion diagram.
To calculate the change in velocity, we take the negative of $\vec v_i$ and add it to $\vec v_f$, to get $\Delta \vec v$

$$\vec v_f + (-\vec v_i) = \Delta v$$

We can also think of $\Delta v$ as what we add to $\vec v_i$ to get $\vec v_f$:

$$\vec v_f=\vec v_i+\Delta \vec v$$

Remember that the displacement is written as $\Delta \vec x$? While it is easiest to think of it as the vector from one spot to another, we can think of it as a "change of position". To do that, we define the position vector of a spot as the vector from the origin to that spot.